Solution:
Given:
Two vessels A and B contain solution of acid and water. In A and B the ratio of acid and water are 7 ∶ 3 and 4 ∶ 1, respectively. They are mixed in the ratio 1 ∶ 2.
Calculation:
In 1 unit of vessel A, quantity of acid = 710×1=710
Quantity of water = 310×1=310
Similarly, in 2 units of vessel B, quantity of acid = 45×2=85
Quantity of water = 15×2=25
The ratio of acid and water in the resulting solution = [(710+85):(310+25)]
=2310:710
⇒ 23 ∶ 7
∴ The ratio of acid and water in the resulting solution is 23 ∶ 7.
