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Vijay invests a sum of ₹5400 and Mohan invests a sum of ₹9400 at the same rate of simple interest per annum. If, at the end of 4 years, Mohan gets ₹360 more interest than Vijay, then find the rate of interest per annum (in percentage).

A3.50

B2.25

C4.75

D5.25

Answer:

B. 2.25

Read Explanation:

Let the rate of interest = (r%)

Simple Interest formula

SI=P×r×t100\text{SI} = \frac{P \times r \times t}{100}
Interest for Vijay and Mohan

  • Vijay:
    5400×r×4100\frac{5400 \times r \times 4}{100}

  • Mohan:
    9400×r×4100\frac{9400 \times r \times 4}{100}

    Difference in interest

(9400−5400)×r×4100=360\frac{(9400 - 5400)\times r \times 4}{100} = 360
4000×r×4100=360\frac{4000 \times r \times 4}{100} = 360

16000r100=360\frac{16000r}{100} = 360

160r = 360

r=360160=2.25r = \frac{360}{160} = 2.25
Final Answer: 2.25% per annum


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