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What is the area of a sector of a circle of radius 14 cm and central angle 45°?(Take π = 22/7)

A67 sq cm

B11 sq cm

C70 sq cm

D77 sq cm

Answer:

D. 77 sq cm

Read Explanation:

Given:

Radius of sector (r) = 14 cm

Central angle (θ) = 45° 

Formula Used:

Area of sector =πr2×(θ/360)= πr^2\times{(θ/360)}

Calculation:

Area of sector

=227×14×14×= \frac{22}{7}\times{14}\times{14}\times(45°/360°)

= 77 cm2

∴ Required area of the sector is 77 cm2


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