What is the degree of p(x)+q(x): $p(x)=4x^4+3x^2+6x+9$,$q(x)=5x^4+6x^3+8$

Challenger App

★

1M+ Downloads

What is the degree of p(x)+q(x):

$p(x)=4x^4+3x^2+6x+9$ , $q(x)=5x^4+6x^3+8$

Answer:

$p(x)=4x^4+3x^2+6x+9$ , $q(x)=5x^4+6x^3+8$

$p(x)+q(x)=9x^4+6x^3+3x^2+6x+17$

degree of p(x)+q(x) =4

Related Questions:

Find the value of k if x - 1 is a factor of $2x^3+x^2-4x+k$

6p^2 -5p-6 = 0.