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What is the largest number if the average of 7 consecutive natural numbers is 43?

A46

B45

C47

D49

Answer:

A. 46

Read Explanation:

If the consecutive 7 natural numbers are a, a+1, a+2, a+3, a+4, a+5, a+6 Average = (7a+21)/7=43 7a+21=43x7 7a+21=301 7a=280 a=280/7 =40 Largest number= a+6 = 40+6 = 46

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