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What is the least five-digit number that when decreased by 7 is divisible by 15, 24, 28, and 32?

A10067

B10087

C10077

D10097

Answer:

B. 10087

Read Explanation:

15 = 3 × 5 24 = 2 × 2 × 2 × 3 28 = 2 × 2 × 7 32 = 2 × 2 × 2 × 2 × 2 LCM of 15, 24, 28 and 32 = 2 × 2 × 2 × 2 × 2 × 3 × 5 × 7 = 3360 The number will be = (3360 × x) + 7 Put x = 3 number = (3360 × 3) + 7 = 10087


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