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What is the least number which when divided by 15, 18 and 36 leaves the same remainder 9 in each case and is divisible by 11?

A1080

B1071

C1269

D1089

Answer:

D. 1089

Read Explanation:

LCM = 2 × 3 × 3 × 5 × 1 × 2 = 180 The required number which is exactly divisible by 11 180x + 9 Put x = 6 = 180 × 6 + 9 = 1089 is divisible by 11.


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