What is the length of the chord whose distance from the centre is 8 cm and radius is 10 cm?
A10 cm
B12 cm
C15 cm
D18 cm
Answer:
B. 12 cm
Read Explanation:
According to the given question
Given:
Radius of circle = 10 cm
Distance from centre = 8 cm
Formula used:
Line perpendicular to the chord passes through the centre divide the chord into two equal areas
According to Pythagoras theorem, the sum of the square of two sides is equal to the square of the longest side
Calculation:
Let the length of chord is AB
According to Pythagoras theorem in triangle AOC
∴ (10)2 = (8)2 + AC2
⇒ AC2 = (10)2 - (8)2
⇒ AC = 6
Now, length of chord is AB = AC + BC and OC divide the chord in two equal parts
∴ AB = AC + BC = 2 $\times$ AC = 2 $\times$ 6 = 12 cm
So, the length of chord is 12 cm
Hence, option (2) is correct