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What is the sum of the numbers between 400 and 500 such that when they are divided by 6, 12 and 16, it leaves no remainder?

A912

B1024

C960

D480

Answer:

A. 912

Read Explanation:

LCM (6, 12, 16) = 48k The required numbers will be in the form of 48k, where k is a natural number. k = 9, 48k = 48 × 9 = 432 k = 10, 48k = 48 × 10 = 480 Only 432 and 480 is the number that are between 400 and 500, and also divisible by 6, 12 and 16 Sum = 432 + 480 = 912


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