What is the sum of the numbers between 400 and 500 such that when they are divided by 6, 12 and 16, it leaves no remainder?
A912
B1024
C960
D480
Answer:
A. 912
Read Explanation:
LCM (6, 12, 16) = 48k
The required numbers will be in the form of 48k, where k is a natural number.
k = 9,
48k = 48 × 9
= 432
k = 10,
48k = 48 × 10
= 480
Only 432 and 480 is the number that are between 400 and 500, and also divisible by 6, 12 and 16
Sum = 432 + 480
= 912