What is the value of:(√18 + √2)²-(√8 + √2)²A14B15C16D17Answer: A. 14 Read Explanation: We need to find:(18+2)2−(8+2)2(\sqrt{18}+\sqrt{2})^2-(\sqrt{8}+\sqrt{2})^2(18+2)2−(8+2)2Step 1: Simplify the square roots18=32,8=22\sqrt{18}=3\sqrt{2}, \qquad \sqrt{8}=2\sqrt{2}18=32,8=22So,(32+2)2−(22+2)2(3\sqrt{2}+\sqrt{2})^2-(2\sqrt{2}+\sqrt{2})^2(32+2)2−(22+2)2=(42)2−(32)2=(4\sqrt{2})^2-(3\sqrt{2})^2=(42)2−(32)2Step 2: Square each term(42)2=16×2=32(4\sqrt{2})^2=16\times2=32(42)2=16×2=32(32)2=9×2=18(3\sqrt{2})^2=9\times2=18(32)2=9×2=18Subtract32-18=14Answer:(14)Answer: (\boxed{14})Answer:(14) Read more in App