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What is the value of:(√18 + √2)²-(√8 + √2)²

A14

B15

C16

D17

Answer:

A. 14

Read Explanation:

We need to find:

(18+2)2−(8+2)2(\sqrt{18}+\sqrt{2})^2-(\sqrt{8}+\sqrt{2})^2

Step 1: Simplify the square roots

18=32,8=22\sqrt{18}=3\sqrt{2}, \qquad \sqrt{8}=2\sqrt{2}

So,

(32+2)2−(22+2)2(3\sqrt{2}+\sqrt{2})^2-(2\sqrt{2}+\sqrt{2})^2
=(42)2−(32)2=(4\sqrt{2})^2-(3\sqrt{2})^2

Step 2: Square each term

(42)2=16×2=32(4\sqrt{2})^2=16\times2=32
(32)2=9×2=18(3\sqrt{2})^2=9\times2=18

Subtract

32-18=14

Answer:(14)Answer: (\boxed{14})


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