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What is the value of (3/5)2×(5/7)23/5)3×(7/5)2=?\frac{(3/5)^2\times(5/7)^{-2}}{3/5)^3\times(7/5)^2}=?

A3/5

B7/3

C3/7

D5/3

Answer:

D. 5/3

Read Explanation:

(3/5)2×(5/7)2(3/5)3×(7/5)2\frac{(3/5)^2\times(5/7)^{-2}}{(3/5)^3\times(7/5)^2}

=(3/5)2×(5/7)2×(5/3)3×(5/7)2=(3/5)^2\times(5/7)^{-2}\times(5/3)^3\times(5/7)^2

=5/3=5/3


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