Question

What is the Value of $\frac{\cos(50^\circ +A)-\sin(40^\circ -A)}{\cos40^\circ \sec40^\circ}$

• A. 0.5
• B. 1
• C. 2
• D. 0

Answer 1

Answer:

D. 0

Solution:

Given:

$\frac{\cos(50^\circ +A)-\sin(40^\circ -A)}{\cos40^\circ \sec40^\circ}$

Calculation:

$\frac{\cos(50^\circ +A)-\sin(40^\circ -A)}{\cos40^\circ \sec40^\circ}$

$\frac{\sin(90 - (50^\circ +A))-\sin(40^\circ -A)}{\cos40^\circ \sec40^\circ}$

$\frac{\sin(40^\circ-A)-\sin(40^\circ -A)}{\cos40^\circ \sec40^\circ}$

⇒ 0

∴ The required answer is 0.

$