AThursday
BWednesday
CFriday
DTuesday
Answer:
B. Wednesday
Read Explanation:
Solution:
Concept:
No. of Odd days | Ordinary Year | Leap Year |
365 ÷ 7 = 52 weeks + 1 odd day | 366 ÷ 7 = 52 weeks + 2 odd day |
Years | No. of odd days |
100 years | 5 |
200 years | 3 |
300 years | 1 |
400 years | 0 |
Note: Multiple of 400 years i.e. 800, 1200, 1600, 2000 have 0 odd days.
Calculating leap year: For Finding the number of leap year (1 - 99) years, divide the number of years by 4 and the quotient will be the number of leap years.
Code for weekdays:
No. of odd days | Day |
0 | Sunday |
1 | Monday |
2 | Tuesday |
3 | Wednesday |
4 | Thursday |
5 | Friday |
6 | Saturday |
2012 = 2000 + 11 years + year 2012
In 2000 years, odd days = 0
In 11 years (from 2001 to 2011), = 11/4 = 2 leap year and 9 normal years.
In 2 leap year, odd days = 4, and 9 normal years = 9 odd days
So total = 4 + 9 = 13 odd days i.e. 13/7 = 6 odd day
In 2012, the number of days up to 22 February = 31 (Jan) + 22 (Feb) = 53/7 = 4 odd days.
Total in 2012 years up to 22 February = 0 + 6 + 4 = 10 odd days = 3 odd days
So, ‘3’ is the code for Wednesday.
Hence, ‘Wednesday’ is the correct answer.
Additional Information
Year - One year has 365 days or 366 days on this basis the year is divided into two parts:
Normal year - It has 365 days.
Leap year - It has 366 days and completely divisible by 4.
Century leap year - The year which is exactly divisible by 400. Example - 1200, 1600, 2000 etc.
Counting of Odd days
Ordinary Year: 365 days (52 weeks + 1 days)
= 1 Odd days
Leap Year: 366 days (52 weeks + 2 days)
= 2 Odd days