A1/6
B4/7
C2/5
D2/3
Answer:
Related Questions:
If 1518=x6=10y=z30\frac{15}{18} = \frac{x}{6} = \frac{10}{y} = \frac{z}{30}1815=6x=y10=30z, then what is the value of x+y+z ?
6711+131522−7333−X=7131106\frac{7}{11}+13\frac{15}{22}-7\frac{3}{33}-X=7\frac{13}{110}6117+132215−7333−X=711013
$$ആണെങ്കിൽ x എത്ര ?
312+14−213=3\frac{1}{2} + \frac{1}{4} - 2\frac{1}{3} =321+41−231=
212+314−415=2\frac{1}{2} + 3\frac{1}{4} - 4\frac{1}{5} =221+341−451=
