Question

Which of the following interchanges of numbers would make the given equation correct?
$6 \times 40 \div 8 + 2 - 5 = 11$

• A. 8, 40
• B. 5,6
• C. 2,6
• D. 2,5

Answer 1

Answer:

C. 2,6

The correct interchange of numbers is 6 and 2.

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Using the BODMAS rule (Brackets, Orders, Division, Multiplication, Addition, Subtraction):

1. Interchange 6 and 2 in the original equation:
   $2 \times 40 \div 8 + 6 - 5 = 11$

2. Step 1: Division ($\div$)
   Divide 40 by 8:
   $40 \div 8 = 5$
   The equation becomes:
   $2 \times 5 + 6 - 5 = 11$

3. Step 2: Multiplication ($\times$)
   Multiply 2 by 5:
   $2 \times 5 = 10$
   The equation becomes:
   $10 + 6 - 5 = 11$

4. Step 3: Addition ($+$)
   Add 10 and 6:
   $10 + 6 = 16$
   The equation becomes:
   $16 - 5 = 11$

5. Step 4: Subtraction ($-$)
   Subtract 5 from 16:
   $16 - 5 = 11$

Since $11 = 11$, the Left Hand Side (LHS) equals the Right Hand Side (RHS), making the equation correct.