If xy = 120 and x^2 + y^2 = 289, then x + y =

Challenger App

★

1M+ Downloads

xy = 120 , x^2 + y^2 = 289 , എങ്കിൽ x + y =

A24

B33

C21

D23

Answer:

(x + y)² = x² + y² + 2xy (x + y)² = 289 + 2 × 120 =289 + 240 =529 (x + y) = √529 =23

Related Questions:

$\sqrt{9}+\sqrt{4}+\sqrt{25}=$

$\frac{\sqrt{36}}{\sqrt5}\times\frac{\sqrt{125}}{5}\times\frac{3}{6}=?$

√10.89 എത്രയാണ്?

$2^{10}$ നോടു എത്ര കൂട്ടിയാൽ $2^{11}$ ലഭിക്കും