If xy = 120 and x^2 + y^2 = 289, then x + y =

Challenger App

★

1M+ Downloads

xy = 120 , x^2 + y^2 = 289 , എങ്കിൽ x + y =

A24

B33

C21

D23

Answer:

(x + y)² = x² + y² + 2xy (x + y)² = 289 + 2 × 120 =289 + 240 =529 (x + y) = √529 =23

Related Questions:

64K⁶⁴ എന്ന സംഖ്യയുടെ വർഗമൂലം കാണുക.

$\sqrt {{30 }+ \sqrt {31}+ \sqrt{22+x}}$

$$find x

$\frac{x}{\sqrt{512}}=\frac{\sqrt{128}}{x}$ x കണ്ടെത്തുക

$\sqrt{\frac1{16}+{\frac19}}=?$