$(x/y)^{5a-3}=(y/x)^{17-3a}$find a

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$(x/y)^{5a-3}=(y/x)^{17-3a}$ find a

B-8

C-7

Answer:

$(x/y)^{5a-3}=(y/x)^{17-3a}$

$(x/y)^{5a-3}=(x/y)^{3a-17}$

$5a-3=3a-17$

$5a-3a=-17+3$

$2a=-14$

$a=-14/2 = -7$

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