Question

y=x³logx ; d²y/dx²=

• A. 5x+6xlogx
• B. 5x-6xlogx
• C. 5x
• D. 6xlogx

Answer 1

Answer:

A. 5x+6xlogx

y=x³logx applying chain rule (uv)'=u'v+v'u dy/dx= x³ x 1/x + logx x 3x^2 = x² + 3x²logx d²y/dx²= 2x + 3x² x 1/x + logx x 6x = 2x + 3x + 6xlogx = 5x + 6xlogx