y=x³logx ; d²y/dx²=

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y=x³logx ; d²y/dx²=

A5x+6xlogx

B5x-6xlogx

C5x

D6xlogx

Answer:

A. 5x+6xlogx

Read Explanation:

y=x³logx applying chain rule (uv)'=u'v+v'u dy/dx= x³ x 1/x + logx x 3x^2 = x² + 3x²logx d²y/dx²= 2x + 3x² x 1/x + logx x 6x = 2x + 3x + 6xlogx = 5x + 6xlogx

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