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Zeros of p(x)=x227p(x) = x^2-27are:

A±9√3

B3√3

C±7√3

DNone of these

Answer:

B. 3√3

Read Explanation:

p(x)=x227=0p(x) = x^2-27=0

x2=27x^2=27

x=±27x=±\sqrt{27}

=±33=±3\sqrt3


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