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A force F is applied on a uniform rod of cross-section A and a force F’ is applied on a uniform rod of cross-section 3A. What is the relation between F and F’ if the pressure on both is the same?

AF/F’ = 1/3

BF/F’ = 3

CF’/F = 1/3

DF/F’ = 1/9

Answer:

A. F/F’ = 1/3

Read Explanation:

Pressure on first rod (P) = F/A Pressure on the second rod (P’) = F’/3A Given; P = P’ F/A = F’/3A F/F’ = 1/3.


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