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ഒരു സമ ബഹുഭുജത്തിന്റെ ഒരു ആന്തരകോണിന്റെ അളവ് 150 ആയാൽ അതിന് എത്ര വശങ്ങൾഉണ്ട് ?

A10

B6

C8

D12

Answer:

D. 12

Read Explanation:

വശങ്ങളുടെ എണ്ണം n ആയാൽ 180(n-2)/n = ആന്തരകോണിൻ്റെ അളവ് 180(n-2)/n = 150° 180n - 360 = 150n 180n - 150n = 360 30n = 360 n = 360/30 = 12


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