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ഒരു സമ ബഹുഭുജത്തിലെ ആന്തര കോണുകളുടെ തുക 540 ആണ് എങ്കിൽ ഒരു കോൺ എത്ര ആണ്?

A90°

B108°

C120°

D150°

Answer:

B. 108°

Read Explanation:

ആന്തര കോണുകളുടെ തുക=(n - 2)180 (n - 2)180 = 540 n - 2 = 540/180 = 3 n = 3 + 2 = 5 ഒരു കോൺ= 540/5 = 108°


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