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The cost of 8A is equal to the cost of 50B. The cost of 19C is 456. The cost of B is twice the cost of 2C. What is the total cost of 3A and 4B together?

A2184

B2022

C2080

D1996

Answer:

A. 2184

Read Explanation:

CP of 8A= CP of 50B =>

A/B=50/8

A : B= 50:8

=>25:4

Let CP of A is 25x and CP of B is 4x

19C = 456

=> C=24

CP of B=2 times the CP of 2C=3×2×243\times{2}\times{24}=96

CP of B = 4x=96

X= 24

CP of A = 25x =25×24=600=25\times{24}=600

3A+4B=3×600+4×96=21843A +4B=3\times{600}+4\times{96}=2184


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