A1B1/2C7/5D5/7Answer: D. 5/7Read Explanation:4(x−1)×(0.5)(3−2x)=(18)x4^{(x-1)} \times (0.5)^{(3-2x)} = (\frac{1}{8})^{x}4(x−1)×(0.5)(3−2x)=(81)x 2(2x−2)×(1/2)(3−2x)=(123)x2^{(2x-2)} \times (1/2)^{(3-2x)}=(\frac{1}{2^3})^x2(2x−2)×(1/2)(3−2x)=(231)x 2(2x−2)×2(2x−3)=2−3x2^{(2x-2 )}× 2^{(2x-3)} = 2^{-3x}2(2x−2)×2(2x−3)=2−3x (2x−2)+(2x−3)=(−3x)(2x-2) + (2x-3) = (-3x)(2x−2)+(2x−3)=(−3x) 4x−5=−3x4x -5 = -3x4x−5=−3x7x=5 7x = 57x=5x=5/7 x = 5/7x=5/7 Read more in App
