A$\frac{18}{5}$
B$\frac{9}{5}$
C$\frac{5}{9}$
D$\frac{5}{18}$
Answer:
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23×43×(65)2(36)4×(16)3= \frac {2^3 \times 4^3 \times (6^5)^2} {(36)^4 \times (16)^3} =(36)4×(16)323×43×(65)2=
105×106107×108=\frac{10^5\times10^6}{10^7\times10^8}=107×108105×106=
(52)2×(51)2(52)1×(51)1\frac{(5^2)^2\times(5^1)^2}{(5^2)^1\times(5^1)^1}(52)1×(51)1(52)2×(51)2ലഘൂകരിക്കുക
(16)2×(32)493×(42)3=\frac{(16)^2 \times (3^2)^4}{9^3 \times (4^2)^3}=93×(42)3(16)2×(32)4=
