Question

$(x/y)^{12}.y^{24}.(z^3)^4=$

• A. $$(xyz)^{6}$$
• B. $$(xyz)^{8}$$
• C. $$(xyz)^{12}$$
• D. $$(xyz)^{24}$$

Answer 1

Answer:

$$(xyz)^{12}$$

$(x/y)^{12}.y^{24}.(z^3)^4$

$=x^{12}\times{y^{24-12}}\times{z^{12}}$

$=x^{12}.y^{12}.z^{12}$

$=(xyz)^{12}$