Challenger App

★

1M+ Downloads

A8 and 6

B2 and 8

C20 and 8

D4 and 20

Answer:

squaring both sides

$2x+9=(13-x)^2$

$2x+9=169-26x+x^2$

$x^2-28x+160=0$

Find two numbers that multiply to 160 and add to 28: $(x-20),(x-8)$

answer is 20&8

Related Questions:

The product of the roots of the quadratic equation $6-5x^2-8x = 0$ is:

x ^ 2 + 7x + 6 = 0

The factors of $x^3+2x^2-5x-6$ is :