A3
B5
C6
D4
Answer:
Related Questions:
(3−23+2)+(3+23−2)= (\frac {\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}})+(\frac {\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}) = (3+23−2)+(3−23+2)=
x512=128x\frac{x}{\sqrt{512}}=\frac{\sqrt{128}}{x}512x=x128find x
