Question

• A. 1
• B. 2
• C. 1/2
• D. 1/4

Answer 1

Answer:

C. 1/2

$\int_0^2 f(x)dx=1$

$\int_0^2 kx =1$

$k[\frac{x^2}{2}]_0^2=1$

$k[\frac{4}{2}]=1$

$2k=1$

$k=\frac{1}{2}$