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11 മുതൽ 49 വരെയുള്ള ഒറ്റ സംഖ്യകളുടെ തുക

A600

B700

C800

D900

Answer:

A. 600

Read Explanation:

Sn=n2(a+an)S_n=\frac{n}{2}(a+a_n)

n=(ana)2+1=49112+1=19+1=20n=\frac{(a_n-a)}{2}+1=\frac{49-11}{2}+1=19+1=20

Sn=202(11+49)S_n=\frac{20}{2}(11+49)

=10×60=600=10 \times 60 = 600


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