Question

14 years ago, the age of a father was three times the age of his son. Now, the father is twice as old as his son. What is the sum of the present ages of the father and the son?

• A. 84 years
• B. 56 years
• C. 42 years
• D. 98 years

Answer 1

Answer:

A. 84 years

father age =A

son age = B

14 years ago

$A-14=3(B-14)$

$A-14=3B-42$

$A=3B-42+14$

$A=3B-42+14$

$A=3B-28$----------------1

present condition

$A=2B$------------------------2

2 in 1

$2B=3B-28$

$B=28$

$A=56$

sum of Age$=28+56=84$