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21000−2999=2^{1000}-2^{999}=

A$2^9$

B$2^{11}$

C$2^{111}$

D$2^{999}$

Answer:

$2^{999}$

Read Explanation:

The value of 21000−29992^{1000} - 2^{999} is 29992^{999}.


  • Find the common factor: Look for the lowest power of 2 present in both terms, which is 29992^{999}.

  • Factor it out: Rewrite the expression by pulling out 29992^{999}:
    21000−2999=2999⋅(21−1)2^{1000} - 2^{999} = 2^{999} \cdot (2^1 - 1)

  • Simplify inside the brackets: Since 21=22^1 = 2, the expression becomes:
    2999⋅(2−1)2^{999} \cdot (2 - 1)

  • Final calculation:
    2999⋅1=29992^{999} \cdot 1 = \mathbf{2^{999}}


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