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2 + 4 + 6 +............100 =

A2550

B2505

C2560

D2530

Answer:

A. 2550

Read Explanation:

There are two simple ways to solve this sum:

Method 1: Formula for Sum of First nn Even Numbers

The formula to find the sum of the first nn even numbers is n(n+1)n(n + 1).

  • In the series 2+4+6++1002 + 4 + 6 + \dots + 100, there are 50 even numbers (n=50n = 50).

  • Sum = 50×(50+1)50 \times (50 + 1)

  • Sum = 50×51=255050 \times 51 = \mathbf{2550}


Method 2: Arithmetic Progression (AP) Formula

In this series:

  • First term (aa) = 2

  • Last term (ll) = 100

  • Number of terms (nn) = 50

The formula for the sum is: Sn=n2(a+l)S_n = \frac{n}{2} (a + l)

  • S50=502(2+100)S_{50} = \frac{50}{2} (2 + 100)

  • S50=25×102=2550S_{50} = 25 \times 102 = \mathbf{2550}

Therefore, 2+4+6++100=25502 + 4 + 6 + \dots + 100 = 2550.


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