Question

2sec²A+ 4cosec²A - 2tan²A - 4cot²A find solution

• A. 2
• B. 6
• C. 8
• D. 4

Answer 1

Answer:

B. 6

$sec^2A=1+tan^2A$

$cosec^2A=1+cot^2A$

$2(1+tan^2A)+4(1+cot^2A)-2tan^2A-4cot^2A$

$2+2tan^2A+4+4cot^2A-2tan^2A-4cot^2A$

$(2+4)+(2tan^2A-2tan^2A)+(4cot^2A-4cot^2A)$

$6+0+0+=6$