A40g
B60g
C80g
D120g
Answer:
B. 60g
Read Explanation:
Understanding Mixture Problems
Mixture problems, especially those involving percentages, are a very common topic in competitive exams. They test your ability to work with proportions and algebraic equations.
The key to solving such problems is to identify the constant component. In this case, when sugar is added, the amount of water remains unchanged.
Step-by-step Calculation:
Initial Solution Breakdown:
The total sugar solution is 300 g.
It contains 40% sugar.
Amount of sugar initially = 40% of 300 g = (40/100) * 300 = 120 g.
Amount of water initially = Total solution - Amount of sugar = 300 g - 120 g = 180 g.
Desired Final State:
We want the new solution to have 50% sugar.
Since only sugar is added, the amount of water remains constant at 180 g.
If the new solution has 50% sugar, it implies that the remaining 50% must be water.
Calculating New Total Solution:
If 180 g of water represents 50% of the new solution, then the total new solution (100%) can be found by doubling the water amount.
New total solution = 180 g / 0.50 = 360 g (or 180 g * 2 = 360 g).
Determining Sugar to be Added:
The new total amount of sugar required in the 360 g solution is 50% of 360 g = (50/100) * 360 = 180 g.
Amount of sugar already present = 120 g.
Sugar to be added = New sugar amount - Initial sugar amount = 180 g - 120 g = 60 g.