Let one man’s 1-day work = m and one woman’s 1-day work = w.
Form equations from given data:
(1)
4 men + 3 women finish in 6 days
6(4m+3w)=1;⇒;4m+3w=61
(2)
5 men + 7 women finish in 4 days
4(5m+7w)=1;⇒;5m+7w=41
Solve the equations:
From (1):
4m+3w=61
From (2):
5m+7w=41
Multiply (1) by 5 and (2) by 4:
20m+15w=65
20m + 28w = 1
Subtract:
13w=1−65=61
⇒w=781
Substitute into (1):
4m+3(781)=61
4m+261=61
4m=61−261=7810=395
m=1565
Work rate of 8 men and 6 women:
8m+6w=8(1565)+6(781)
=15640+15612=15652=31
Time required:
Time=rate1=1/31=3 days
Final Answer:
8 men and 6 women will complete the work in 3 days.