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4 men and 3 women finish a job in 6 days, and 5 men and 7 women can do the same job in 4 days. How long will 8 men and 6 women take to do the same job?

A6 days

B3 days

C9 days

D8 days

Answer:

B. 3 days

Read Explanation:

Let one man’s 1-day work = m and one woman’s 1-day work = w.

Form equations from given data:

(1)
4 men + 3 women finish in 6 days
6(4m+3w)=1;⇒;4m+3w=166(4m + 3w) = 1 ;\Rightarrow; 4m + 3w = \frac{1}{6}

(2)
5 men + 7 women finish in 4 days

4(5m+7w)=1;⇒;5m+7w=144(5m + 7w) = 1 ;\Rightarrow; 5m + 7w = \frac{1}{4}
Solve the equations:

From (1):
4m+3w=164m + 3w = \frac{1}{6}

From (2):
5m+7w=145m + 7w = \frac{1}{4}

Multiply (1) by 5 and (2) by 4:

20m+15w=5620m + 15w = \frac{5}{6}
20m + 28w = 1

Subtract:

13w=1−56=1613w = 1 - \frac{5}{6} = \frac{1}{6}
⇒w=178\Rightarrow w = \frac{1}{78}

Substitute into (1):

4m+3(178)=164m + 3\left(\frac{1}{78}\right) = \frac{1}{6}
4m+126=164m + \frac{1}{26} = \frac{1}{6}
4m=16−126=1078=5394m = \frac{1}{6} - \frac{1}{26} = \frac{10}{78} = \frac{5}{39}
m=5156m = \frac{5}{156}

Work rate of 8 men and 6 women:

8m+6w=8(5156)+6(178)8m + 6w = 8\left(\frac{5}{156}\right) + 6\left(\frac{1}{78}\right)

=40156+12156=52156=13= \frac{40}{156} + \frac{12}{156} = \frac{52}{156} = \frac{1}{3}

Time required:

Time=1rate=11/3=3 days\text{Time} = \frac{1}{\text{rate}} = \frac{1}{1/3} = 3 \text{ days}

Final Answer:

8 men and 6 women will complete the work in 3 days.


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