Question

4851A53B is divisible by 9 and B is an even number, then find the sum of all the values of A.

• A. 21
• B. 19
• C. 20
• D. 18

Answer 1

Answer:

A. 21

4851A53B is divisible by 9 and B is an even number, A number is divisible by 9 if the sum of its digits is divisible by 9. As the starting four digits 4851 (4 + 5 + 8 + 1 = 18 is divisible by 9) ⇒ For the number to be divisible by 9, next four digits A53B, (A + 5 + 3 + B) should be a multiple of 9 As B is an even number, taking all the possible case for the value of A, ⇒ A53B = A + 8 + B, Possible values of B = 0, 2, 4, 6 and 8 Possible values of A (corresponding to values of B) = 1, 8, 6, 4 and 2 ∴ Sum of all possible value of A = 21