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6 men can complete a work in 10 days. They start the work and after 2 days 2 men leave. In how many days will the work be completed by the remaining men?

A9

B7

C12

D8

Answer:

C. 12

Read Explanation:

Solution: Given: 6 men can complete a work in 10 days. 2 men leave after 2 days of work. Concept used: M1 × D1 = M2 × D2 Where M1 is no. of men working on D1 days and M2 is no. of men working on D2 days Calculation: Let, the work completed by remaining men be 'a'. According to the question, After 2 days, the remaining men = 6 - 2 = 4 Now, ⇒ 6 × 10 = 6 × 2 + 4 × a ⇒ 60 = 12 + 4a ⇒ 4a = 48 ⇒ a = 12 ∴ The remaining men will complete the work in 12 days.


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