Solution:
Given:
6 men can complete a work in 10 days.
2 men leave after 2 days of work.
Concept used:
M1 × D1 = M2 × D2
Where M1 is no. of men working on D1 days and
M2 is no. of men working on D2 days
Calculation:
Let, the work completed by remaining men be 'a'.
According to the question,
After 2 days, the remaining men = 6 - 2 = 4
Now,
⇒ 6 × 10 = 6 × 2 + 4 × a
⇒ 60 = 12 + 4a
⇒ 4a = 48
⇒ a = 12
∴ The remaining men will complete the work in 12 days.