Challenger App

No.1 PSC Learning App

1M+ Downloads
6 men can complete a work in 10 days. They start the work and after 2 days 2 men leave. In how many days will the work be completed by the remaining men?

A9

B7

C12

D8

Answer:

C. 12

Read Explanation:

Solution: Given: 6 men can complete a work in 10 days. 2 men leave after 2 days of work. Concept used: M1 × D1 = M2 × D2 Where M1 is no. of men working on D1 days and M2 is no. of men working on D2 days Calculation: Let, the work completed by remaining men be 'a'. According to the question, After 2 days, the remaining men = 6 - 2 = 4 Now, ⇒ 6 × 10 = 6 × 2 + 4 × a ⇒ 60 = 12 + 4a ⇒ 4a = 48 ⇒ a = 12 ∴ The remaining men will complete the work in 12 days.


Related Questions:

A pipe can fill a tank in 9 hours. Another pipe can empty the filled tank in 27 hours. If both the pipes are opened simultaneously, then the time (in hours) in which the tank will be two-third filled, is:
A man running at a speed of 15 km/hr crosses a bridge in 3 minutes. What is the length of the bridge?
Vijay can do a piece of work in 4 hours. Ajay can do it in 28 hours. With the assistance of Amit, they completed the work in 3 hours. In how many hours can Amit alone do it?
രണ്ട് പൈപ്പുകൾക്ക് യഥാക്രമം 3 മണിക്കൂറും 4 മണിക്കൂറും കൊണ്ട് ഒരു ജലസംഭരണി നിറയ്ക്കാൻ കഴിയും, ഒരു മാലിന്യ പൈപ്പിന് 2 മണിക്കൂർ കൊണ്ട് അത് ശൂന്യമാക്കാം. മൂന്ന് പൈപ്പുകളും തുറന്നിരിക്കുകയാണെങ്കിൽ, ജലസംഭരണി നിറയാൻ എടുക്കുന്ന സമയം എത്ര?
Pipe P can fill 4/9 part of a tank in 28 hours and pipe Q can fill 3/5 part of the same tank in 27 hours. Both P and Q were kept open for 3 hours, then both were closed. Pipe R alone was then opened and it emptied the water in the tank in 8 hours. Pipes P, Q and R together can fill the empty tank in: