$9^6 \times 12^4 \times 7^7$എന്ന സംഖ്യയുടെ പ്രൈം ഘടകങ്ങളുടെ ആകെ തുക എത്രയാണ്? A13B12C11D14Answer: B. 12 Read Explanation: Express in prime factors9=329=3^29=3296=(32)6=3129^6 = (3^2)^6 = 3^{12} 96=(32)6=31212=22×3 12 = 2^2\times312=22×3124=(22×3)4=28×3412^4 =(2^2 \times 3)^4 = 2^8 \times 3^4124=(22×3)4=28×34777^777 is already a prime powercombine all96×124×77=312×(28×34)×779^6 \times 12^4 \times 7^7 = 3^{12}\times(2^8\times3^4)\times7^796×124×77=312×(28×34)×77=28×312+4×77= 2^8\times3^{12+4}\times7^7=28×312+4×77=28×316×77= 2^8\times 3^{16}\times7^7=28×316×77 The distinct prime factors are 2,3,7sum of factors = 2 +3 + 7 = 12 Read more in App