Question

$\frac{(16)^2 \times (3^2)^4}{9^3 \times (4^2)^3}=$

• A. 9/16
• B. 16/9
• C. 5/4
• D. 4/5

Answer 1

Answer:

A. 9/16

$\frac{(16)^2 \times (3^2)^4}{9^3 \times (4^2)^3}$

$=\frac{16^2\times9^4}{9^3\times16^3}$

$=\frac{9}{16}$