Challenger App

No.1 PSC Learning App

1M+ Downloads

9x+3x90=09^x+3^x-90=0എങ്കിൽ x എത്ര ?

A3

B6

C4

D2

Answer:

D. 2

Read Explanation:

9x+3x90=09^x+3^x-90=0

32x+3x90=03^{2x}+3^x-90=0

32x+3x=903^{2x}+3^x=90

3x(32+1)=903^x(3^2+1)=90

3x×(9+1)=903^x\times(9+1)=90

3x=90/10=93^x = 90/10 = 9

3x=323^x=3^2

x=2x=2 

 

 


Related Questions:

(0.04)(1.5)(0.04)^{(-1.5)}എത്ര?

The grad • at the point (1.-2.-1) for ^ (x, y, z) = 3x²y-y³z² is
4^n = 1024 ആയാൽ 4^(n - 3) എത്ര?
image.png
If √2^n = 128 ,then the value of n is