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A 120 m long train crosses a man walking at a speed of 8.5 km/h in the opposite direction in 12 seconds. What is the speed (in km/h) of the train?

A23.3

B27.5

C29.1

D31.5

Answer:

B. 27.5

Read Explanation:

$S_1+S_2=d/t$

$S_2=8.5kmph$

$d=120m$

$t=12s$

$S_1+8.5=\frac{120}{12}\times \frac{18}{5}$

$S_1+8.5=10\times \frac{18}{5}=36$

$S_1=36-8.5$

$S_1=27.5kmph$


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