Total solution = 40 L
Ratio salt : water = 3 : 5
Find initial quantities
Total parts = 3 + 5 = 8
Salt = ( \frac{3}{8} \times 40 = 15 ) L
Water = ( \frac{5}{8} \times 40 = 25 ) L
Let x litres of water be added
New water = ( 25 + x )
Salt remains = 15
New ratio = 3 : 7
So,
25+x15=73
Step 3: Solve
15×7=3(25+x)
105=75+3x
30=3x
x=10
Final Answer: 10 litres of water