Question

A and B fires a group of birds. If A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times. A has killed

• A. 30 birds
• B. 60 birds
• C. 72 birds
• D. 90 birds

Answer 1

Answer:

A. 30 birds

Let the total number of shots be x.

Then shots fired by $A= \frac{5}{8}x$

shots fired by $B=\frac{ 5}{8}x$

Killing shots by $A=\frac{1}{3} of \frac{5}{8}x = \frac{5x}{24}$

Shots missed by $B=\frac{1}{2} of \frac{3}{8}x = \frac{3x}{16}=27$

$\frac{3x}{16} = 27$ or $x=(27\times{\frac{16}{3}}) =144$

Birds killed by $A=\frac{5x}{24}= (\frac{5}{24}\times{144}) =30$