Let’s solve step by step.
Assume everyone is facing the centre, so:
Let’s place A at position 0 (to simplify the circle).
1) E is third to the left of A
From A (0), move 3 clockwise → E = 3
2) C is second to the left of E
From E (3), move 2 clockwise → C = 5
So far:
Remaining seats: 1, 2, 4, 6 for B, D, F, G
Use B-related conditions
3) G is third to the right of B
Right = anticlockwise
So: G = B − 3 (mod 7)
4) D is second to the right of B
So: D = B − 2 (mod 7)
Thus around B (anticlockwise order):
B → (x−1) → D → G
Try valid placements
Check possible B positions from remaining slots:
Try B = 4
Now placed:
Remaining seats:
So final arrangement:
A = 0
G = 1
D = 2
E = 3
B = 4
C = 5
F = 6
All conditions check out.
Question
How many people sit between D and A when counted from the left of D?
From D (2), moving clockwise (left):
3 (E)
4 (B)
5 (C)
6 (F)
0 (A)
People between D and A = E, B, C, F = 4 people
Final Answer: 4