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A bag contains ₹10, ₹5, and ₹2 coins in the ratio 1: 2: 3. If the total amount of money in the bag is ₹390, find the number of coins of each kind.

A15 coins of ₹10, 30 of ₹5, and 45 of ₹2

B20 coins of ₹10, 40 of ₹5, and 60 of ₹2

C12 coins of ₹10, 24 of ₹5, and 36 of ₹2

D10 coins of ₹10, 20 of ₹5, and 45 of ₹2

Answer:

A. 15 coins of ₹10, 30 of ₹5, and 45 of ₹2

Read Explanation:

Let the number of ₹10, ₹5, and ₹2 coins be (x), (2x), and (3x) respectively, since their ratio is 1 : 2 : 3.

The total value is:

  • ₹10 coins: (10x)

  • ₹5 coins: (5 \times 2x = 10x)

  • ₹2 coins: (2 \times 3x = 6x)

So,

10x + 10x + 6x = 390
26x = 390
x=39026=15x = \frac{390}{26} = 15

Therefore:

  • ₹10 coins = (1×15=15)(1 \times 15 = 15)

  • ₹5 coins = (2×15=30)(2 \times 15 = 30)

  • ₹2 coins =(3×15=45) (3 \times 15 = 45)

Answer:

  • ₹10 coins = 15

  • ₹5 coins = 30

  • ₹2 coins = 45

Verification:

  • 15×10=15 \times 10 = ₹150

  • 30×5=30 \times 5 = ₹150

  • 45×2=45 \times 2 = ₹90

Total = ₹150 + ₹150 + ₹90 = ₹390


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