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A bag has Rs.785 in the denomination of Rs. 2, Rs.5 and Rs.10 coins.The coins are in the ratio of 6:9:10. How many coins of Rs.5 are in the bag:

A60

B12

C45

D24

Answer:

C. 45

Read Explanation:

Understanding the Problem

This problem involves calculating the number of coins of a specific denomination given the total value of coins, the denominations present, and the ratio of the number of coins of each denomination.

Key Concepts Involved:

  • Ratio: A comparison of two or more quantities.
  • Total Value: The sum of the values of all the coins.
  • Denominations: The face value of the currency (e.g., Rs. 2, Rs. 5, Rs. 10).

Steps to Solve:

  1. Represent the number of coins: Since the coins are in the ratio 6:9:10, let the number of Rs. 2, Rs. 5, and Rs. 10 coins be 6x, 9x, and 10x respectively.
  2. Calculate the value of each denomination:
    • Value of Rs. 2 coins = (Number of Rs. 2 coins) imes (Face value of Rs. 2 coin) = 6x imes 2 = 12x
    • Value of Rs. 5 coins = (Number of Rs. 5 coins) imes (Face value of Rs. 5 coin) = 9x imes 5 = 45x
    • Value of Rs. 10 coins = (Number of Rs. 10 coins) imes (Face value of Rs. 10 coin) = 10x imes 10 = 100x
  3. Form an equation for the total value: The sum of the values of all denominations equals the total amount in the bag.

    12x + 45x + 100x = 785

  4. Solve for 'x': Combine the terms on the left side of the equation.

    157x = 785

    Divide both sides by 157:

    x = 785 / 157

    x = 5

  5. Calculate the number of Rs. 5 coins: The number of Rs. 5 coins is represented by 9x. Substitute the value of x found in the previous step.

    Number of Rs. 5 coins = 9 imes 5

    Number of Rs. 5 coins = 45

Exam-Oriented Points:

  • Problems involving ratios and total values are common in competitive exams.
  • Carefully identify the ratio and the denominations given in the question.
  • Ensure accurate calculation of the value contributed by each denomination.
  • The variable 'x' represents a common multiplier for the ratio.

Related Questions:

ഒരു ചതുരത്തിന്റെ നീളവും വീതിയും 5 : 3 എന്ന അംശബന്ധത്തിലാണ്. നീളം 40 മീറ്ററായാൽ വീതി എത്ര ?
രണ്ടാമത്തെ സംഖ്യ ആദ്യ സംഖ്യയുമായി ബന്ധപ്പെട്ടിരിക്കുന്ന പോലെ മൂന്ന്നാമത്തെ സംഖ്യയുടെ ബന്ധപ്പെട്ട ഓപ്ഷൻ തിരഞ്ഞെടുക്കുക 31 : 90 : : 43 : ?
The third proportional to x and x + 100 is 405, find the value of x (where x > 100).
The fourth proportion of 12, 24 and 45 is:
5 : 7 = x : 35 ആണെങ്കിൽ x കണ്ടെത്തുക.