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A can do 15\frac{1}{5}th of a work in 4 days and B can do 16\frac{1}{6}th of the same work in 5 days. In how many days they can finish the work, if they work together?

A12

B20

C15

D30

Answer:

A. 12

Read Explanation:

Solution;

A can do 15\frac{1}{5}th work in 4days.

Efficiency of A = 14×5=120\frac{1}{4\times5}=\frac{1}{20}

B can do 16\frac{1}{6}th of the work in 5days.

Efficiency of B = 16×5=130\frac{1}{6\times5}=\frac{1}{30}

Combined Efficiency of A and B is = 120+130\frac{1}{20}+\frac{1}{30}

=3+260=560=112=\frac{3+2}{60}=\frac{5}{60}=\frac{1}{12}

A and B together can complete the work in 12 days.

Shortcut:

image.png

A can do 1/5th of a work in = 4 days

A can do the whole work in = 4×5=20days4\times 5 = 20 days

B can do 1/6th of the same work in = 5 days

B can do the whole work in = 5×6=30days5 \times 6 = 30 days

From the following figure

Total work = 60

Total efficiency of A and B = 2 + 3 = 5

A and B together can complete the whole work in = 605=12days\frac{60}{5} = 12 days


Related Questions:

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ഒരു വാഹനം യാത്രയുടെ ആദ്യത്തെ 120 കി.മീറ്റർ ദൂരം ശരാശരി 30 കിമീ/മണിക്കൂർ വേഗത്തിലും അടുത്ത 120 കീ മീറ്റർ 20 കിമീ/മണിക്കൂർ വേഗത്തിലുമാണ് സഞ്ചരിച്ചത് . എന്നാൽ മുഴുവൻ യാത്രയിലെയും ശരാശരി വേഗം എത്രയാണ് ?
There are 3 taps, A, B and C, in a tank. These can fill the tank in 10 h, 20 h and 25 h, respectively. At first, all three taps are opened simultaneously. After 2 h, tap C is closed and tap A and B keep running. After 4 h, tap B is also closed. The remaining tank is filled by tap A alone. Find the percentage of work done by tap A itself.