A circular shaft is subjected to a twisting moment T and bending moment M. The ratio of Maximum bending stress to Maximum shear stress is given by:A2M/TBM/TC2T/MDM/2TAnswer: C. 2T/M Read Explanation: Maximum bending stress, σb=MyI=MZ=32Mπd3\sigma_{b} =\frac{My}{I} = \frac{M}{Z} =\frac{32M}{\pi d ^ 3}σb=IMy=ZM=πd332M ; Maximum shear stress, τ=16Tpid3⇒σbτ=2MT\tau= \frac {16T}{pi d ^ 3} \Rightarrow \frac{\sigma_b}{\tau} =\frac{2M}{ T}τ=pid316T⇒τσb=T2M Read more in App