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A circular shaft is subjected to a twisting moment T and bending moment M. The ratio of Maximum bending stress to Maximum shear stress is given by:

A2M/T

BM/T

C2T/M

DM/2T

Answer:

C. 2T/M

Read Explanation:

Maximum bending stress, σb=MyI=MZ=32Mπd3\sigma_{b} =\frac{My}{I} = \frac{M}{Z} =\frac{32M}{\pi d ^ 3} ; Maximum shear stress, τ=16Tpid3σbτ=2MT\tau= \frac {16T}{pi d ^ 3} \Rightarrow \frac{\sigma_b}{\tau} =\frac{2M}{ T}


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Consider the following relation for the torsional stiffness (Кт)

1.KT=TθK_T=\frac {T}{\theta}

2.KT=GJLK_T=\frac {GJ}{L}

3.KT=GθLK_T=\frac {G\theta}{L}